Let I= current through a conductor,

Let $\mathrm{I}=$ current through a conductor, $\mathrm{R}=$ its resistance and $\mathrm{V}=$ potential difference across its ends. According to Ohm’s law, product of two of these quantities equals the third. Obtain Ohm’s law from dimensional analysis. Dimensional formulae for $R$ and $V$ are $\left[\mathrm{ML}^{2} \mathrm{I}^{-2} \mathrm{~T}^{-3}\right]$ and $\left[\mathrm{ML}^{2} \mathrm{~T}^{-3} \mathrm{~J}^{-1}\right]$ respectively


Dimension of $R=\left[\mathrm{ML}^{2} \mathrm{I}^{-2} \mathrm{~T}^{-3}\right]$

Dimension of $\mathrm{V}=\left[\mathrm{ML}^{2} \mathrm{~T}^{-3} \mathrm{~F}^{-1}\right]$

Now, $\mathrm{R}=\left[\mathrm{ML}^{2} \mathrm{~T}^{-2} \mathrm{~T}^{-3}\right]=\left[\mathrm{ML}^{2} \mathrm{I}^{-1} \mathrm{~T}^{-3}\right] /[\mathrm{I}]=\mathrm{V} /[\mathrm{I}]=\mathrm{V} / \mathrm{I}$

or, $V=I R$


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