Let k be an integer such that triangle with vertices (k, –3k), (5, k) and (–k, 2) has area 28 sq.
Question:

Let k be an integer such that triangle with vertices (k, –3k), (5, k) and (–k, 2) has area 28 sq. units. Then the orthocentre of this triangle is at the point : 

  1. $\left(2, \frac{1}{2}\right)$

  2. $\left(2,-\frac{1}{2}\right)$

  3. $\left(1, \frac{3}{4}\right)$

  4. $\left(1,-\frac{3}{4}\right)$


Correct Option: 1

Solution:

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