Question:
Let the equations of two sides of a triangle be $3 x$ $-2 y+6=0$ and $4 x+5 y-20=0$. If the orthocentre of this triangle is at $(1,1)$, then the equation of its third side is :
Correct Option: , 4
Solution:
Equation of $\mathrm{AB}$ is
$3 x-2 y+6=0$
equation of $\mathrm{AC}$ is
$4 x+5 y-20=0$
Equation of BE is
$2 x+3 y-5=0$
Equation of CF is $5 x-4 y-1=0$
$\Rightarrow$ Equation of $\mathrm{BC}$ is $26 \mathrm{x}-122 \mathrm{y}=1675$
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