Mark the correct alternative in each of the following:
Question:

Mark the correct alternative in each of the following:

A die is thrown once. The probability of getting a prime number is

(a) $\frac{2}{3}$

(b) $\frac{1}{3}$

(c) $\frac{1}{2}$

(d) $\frac{1}{6}$                                  [CBSE 2013]

 

Solution:

In a single throw of a die, the possible outcomes are 1, 2, 3, 4, 5 and 6.

∴ Total number of outcomes = 6

The favourable outcomes are 2, 3 and 5.

So, the number of favourable outcomes are 3.

$\therefore \mathrm{P}($ getting a prime number $)=\frac{\text { Favourable number of outcomes }}{\text { Total number of outcomes }}=\frac{3}{6}=\frac{1}{2}$

Hence, the correct answer is option C.

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