Question:
Multiply:
(3x2 + y2) by (2x2 + 3y2)
Solution:
To multiply, we will use distributive law as follows:
$\left(3 x^{2}+y^{2}\right)\left(2 x^{2}+3 y^{2}\right)$
$=3 x^{2}\left(2 x^{2}+3 y^{2}\right)+y^{2}\left(2 x^{2}+3 y^{2}\right)$
$=6 x^{4}+9 x^{2} y^{2}+2 x^{2} y^{2}+3 y^{4}$
$=6 x^{4}+11 x^{2} y^{2}+3 y^{4}$
Thus, the answer is $6 x^{4}+11 x^{2} y^{2}+3 y^{4}$.
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