On treating a compound with warm dil.
Question:

On treating a compound with warm dil. $\mathrm{H}_{2} \mathrm{SO}_{4}$, gas $\mathrm{X}$ is evolved which turns $\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}$ paper acidified with dil. $\mathrm{H}_{2} \mathrm{SO}_{4}$ to a green compound $\mathrm{Y} . \mathrm{X}$ and $\mathrm{Y}$ respectively are :

  1. $X=S O_{2}, Y=C r_{2}\left(S O_{4}\right)_{3}$

  2. $\mathrm{X}=\mathrm{SO}_{2}, \mathrm{Y}=\mathrm{Cr}_{2} \mathrm{O}_{3}$

  3. $\mathrm{K}=\mathrm{SO}_{3}, \mathrm{Y}=\mathrm{Cr}_{2} \mathrm{O}_{3}$

  4. $\mathrm{X}=\mathrm{SO}_{3}, \mathrm{Y}=\mathrm{Cr}_{2}\left(\mathrm{SO}_{4}\right)_{3}$


Correct Option: 1

Solution:

$\underset{(\mathrm{X})}{\mathrm{SO}_{2}}+\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}+\mathrm{H}_{2} \mathrm{SO}_{4} \longrightarrow \underset{(\mathrm{Y})}{\mathrm{Cr}_{2}\left(\mathrm{SO}_{4}\right)_{3}}+\mathrm{K}_{2} \mathrm{SO}_{4}+\mathrm{H}_{2} \mathrm{O}$

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