P is a point on the bisector of ∠ABC.
Question:

P is a point on the bisector of ∠ABC. If the line through P, parallel to BA meet BC at Q, prove that BPQ is an isosceles triangle.

Solution:

Given we have P is a point on the bisector of ∠ABC and draw the line through P parallel to BA and meet BC at Q.

To prove $\triangle B P Q$ is an isosceles triangle.

Proof $\angle 1=\angle 2$ $[\because B P$ is bisector of $\angle B$ (given)]

Now, $\angle 1=\angle 3$ [alternate interior angles as $P Q \| A B$ ]

$\therefore$ $\angle 2=\angle 3$

$\Rightarrow$ $P Q=B Q \quad$ [sides opposite to equal angles are equal]

Hence, $\triangle B P Q$ is an isosceles triangle.

Hence proved.

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