Prove
Question:

$\frac{(\log x)^{2}}{x}$

Solution:

Let $\log |x|=t$

$\therefore \frac{1}{x} d x=d t$

$\Rightarrow \int \frac{(\log |x|)^{2}}{x} d x=\int t^{2} d t$

$=\frac{t^{3}}{3}+\mathrm{C}$

$=\frac{(\log |x|)^{3}}{3}+\mathrm{C}$

 

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