Prove

Question:

$\int\left(2 x-3 \cos x+e^{x}\right) d x$

Solution:

$\int\left(2 x-3 \cos x+e^{x}\right) d x$

$=2 \int x d x-3 \int \cos x d x+\int e^{x} d x$

$=\frac{2 x^{2}}{2}-3(\sin x)+e^{x}+\mathrm{C}$

$=x^{2}-3 \sin x+e^{x}+\mathrm{C}$

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