Prove that the function
Question:

Prove that the function $f$ given by $f(x)=\log \sin x$ is strictly increasing on $\left(0, \frac{\pi}{2}\right)$ and strictly decreasing on $\left(\frac{\pi}{2}, \pi\right)$.

Solution:

We have,

$f(x)=\log \sin x$

$\therefore f^{\prime}(x)=\frac{1}{\sin x} \cos x=\cot x$

In interval $\left(0, \frac{\pi}{2}\right), f^{\prime}(x)=\cot x>0$.

$\therefore f$ is strictly increasing in $\left(0, \frac{\pi}{2}\right)$.

In interval $\left(\frac{\pi}{2}, \pi\right), f^{\prime}(x)=\cot x<0$

$\therefore f$ is strictly decreasing in $\left(\frac{\pi}{2}, \pi\right)$.

Administrator

Leave a comment

Please enter comment.
Please enter your name.