Question:
Reaction of an inorganic sulphite $\mathrm{X}$ with dilute $\mathrm{H}_{2} \mathrm{SO}_{4}$ generates compound Y. Reaction of $Y$ with $\mathrm{NaOH}$ gives $X$. Further, the reaction of $\mathrm{X}$ with $\mathrm{Y}$ and water affords compound Z. Y and Z, respectively, are:
Correct Option: , 3
Solution:
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