Question:
Reaction of an inorganic sulphite $\mathrm{X}$ with dilute $\mathrm{H}_{2} \mathrm{SO}_{4}$ generates compound $\mathrm{Y}$. Reaction of $\mathrm{Y}$ with $\mathrm{NaOH}$ gives $X$. Further, the reaction of $X$ with $\mathrm{Y}$ and water affords compound $\mathrm{Z}$. $\mathrm{Y}$ and $Z$, respectively, are:
Correct Option: 2,
Solution:
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