Question:
Region I and II are separated by a spherical surface of radius $25 \mathrm{~cm}$. An object is kept in region $\mathrm{I}$ at a distance of $40 \mathrm{~cm}$ from the surface. The distance of the image from the surface is :
Correct Option: , 4
Solution:
$\frac{\mu_{2}}{\mathrm{~V}}-\frac{\mu_{1}}{\mathrm{u}}=\frac{\mu_{2}-\mu_{1}}{\mathrm{R}}$
$\frac{1.4}{v}-\frac{1.25}{-40}=\frac{1.4-1.25}{-25}$
$\frac{1.4}{v}=-\frac{0.15}{25}-\frac{1.25}{40}$
$\mathrm{v}=-37.58 \mathrm{~cm}$
Hence option (4)
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