Solubility product of silver bromide
Question:

Solubility product of silver bromide is $5.0 \times 10^{-13}$. The quantity of potassium bromide (molar mass taken as $120 \mathrm{~g} \mathrm{~mol}^{-1}$ ) to be added to 1 litre of $0.05 \mathrm{M}$ solution of silver nitrate to start the precipitation of $\mathrm{AgBr}$ is :-

  1. $5.0 \times 10^{-8} \mathrm{~g}$

  2. $1.2 \times 10^{-10} \mathrm{~g}$

  3. $1.2 \times 10^{-9} \mathrm{~g}$

  4. $6.2 \times 10^{-5} \mathrm{~g}$


Correct Option: , 3

Solution:

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