Solve the following
Question:

Solve:

$\frac{3(y-5)}{4}-4 y=3-\frac{(y-3)}{2}$

Solution:

$\frac{3(y-5)}{4}-4 y=3-\frac{(y-3)}{2}$

$\Rightarrow \frac{3 y-15}{4}-4 y=3-\frac{y-3}{2}$

$\Rightarrow \frac{3 y-15-16 y}{4}=3-\frac{y-3}{2} \quad($ L. C.M. of 4 and 1 is 4$)$

$\Rightarrow \frac{-13 y-15}{4}=\frac{6-y+3}{2}$

$\Rightarrow \frac{-13 y-15}{4}=\frac{9-y}{2}$

$\Rightarrow 2(-13 y-15)=4(9-y)$

$\Rightarrow-26 y-30=36-4 y$

$\Rightarrow-26 y+4 y=36+30$

$\Rightarrow-22 y=66$

$\Rightarrow 22 y=-66 \quad$ (multiplying both the sides with a $-$ ve sign $)$

$\Rightarrow y=-\frac{66}{22}=-3$

$\therefore y=-3$