Solve the following
Question:

Identify the reagent(s) ‘A’ and condition(s) for the reaction:

  1.  $\mathrm{A}=\mathrm{HCl}$; Anhydrous $\mathrm{AlCl}_{3}$

  2. $\mathrm{A}=\mathrm{HCl}, \mathrm{ZnCl}_{2}$

  3. $\mathrm{A}=\mathrm{Cl}_{2}$; UV light

  4.  $\mathrm{A}=\mathrm{Cl}_{2}$; dark, Anhydrous $\mathrm{AlCl}_{3}$


Correct Option: , 3

Solution:

For substitution at allylic position in the given compound, the reagent used is $\mathrm{Cl}_{2} /$ uv light.

The reaction is free radical halogenation.

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