Question:
Consider that a $d^{6}$ metal ion $\left(\mathrm{M}^{2+}\right)$ forms a complex with aqua ligands, and the spin only magnetic moment of the complex is $4.90 \mathrm{BM}$. The geometry and the crystal field stabilization energy of the complex is :
Correct Option: , 2
Solution:
Spin only magnetic moment $=4 \cdot 9=\sqrt{n(n+2)}$
$\therefore$ number of unpaired electrons $=4$
Two possible arrangements are
So, option (b) is correct.
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