Question:
A particle starts from a point $A$ and travels along the solid curve shown in the given figure. Find approximately the position B of the particle such that the average velocity between the positions $A$ and $B$ has the same direction as the instantaneous velocity at $B$.
Solution:
Direction of instantaneous velocity of point $B$ must be same as direction of average velocity $\overrightarrow{A B}$. So, point is approximately $(5,3)$
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