Solve this
Question:

if$\frac{1}{4 !}+\frac{1}{5 !}=\frac{x}{6 !}$, find the value of $x$

 

Solution:

To Find: Value of n

Given: $\frac{1}{4 !}+\frac{1}{5 !}=\frac{x}{6 !}$

Formula Used: $n !=(n) \times(n-1) \times(n-2) \times(n-3)$ $3 \times 2 \times 1$

Now, $\frac{1}{4 !}+\frac{1}{5 !}=\frac{x}{6 !}$

$\Rightarrow \frac{1}{24}+\frac{1}{120}=\frac{x}{720}(4 !=24,5 !=120)$

$\Rightarrow \frac{5+1}{120}=\frac{x}{720}$

$\Rightarrow \frac{6}{120}=\frac{x}{720}$

$\Rightarrow x=36$

 

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