Solve this following
Question:

Prove that

$f(x)=\left\{\begin{array}{l}5 x-4, \text { when } 0<x \leq 1 \\ 4 x^{2}-3 x, \text { when } 1<x<2\end{array}\right.$ is continuous at $x=1$

Solution:

 

Administrator

Leave a comment

Please enter comment.
Please enter your name.