Question:
Mark $(\sqrt{)})$ against the correct answer in the following:
If $y=\tan ^{-1}\left(\frac{a \cos x-b \sin x}{b \cos x+a \sin x}\right)$ then $\frac{d y}{d x}=?$
A. $\frac{a}{b}$
B. $\frac{-b}{a}$
C. 1
D. $-1$
Solution:
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