Solve this following
Question:

Let $y=y(x)$ be a solution of the differential equation, $\sqrt{1-x^{2}} \frac{d y}{d x}+\sqrt{1-y^{2}}=0,|x|<1$.

If $y\left(\frac{1}{2}\right)=\frac{\sqrt{3}}{2}$, then $y\left(\frac{-1}{\sqrt{2}}\right)$ is equal to

1. $-\frac{\sqrt{3}}{2}$

2. $\frac{1}{\sqrt{2}}$

3. $\frac{\sqrt{3}}{2}$

4. $-\frac{1}{\sqrt{2}}$

Correct Option: , 2

Solution: