Solve this following
Question:

If $A$ and $B$ are invertible square matrices of the same order then $(A B)^{-1}=?$

A. $A B^{-1}$

B. $A^{-1} B$

C. $\mathrm{A}^{-1} \mathrm{~B}^{-1}$

D. $B^{-1} A^{-1}$

Solution:

$(A B)^{-1}=B^{-1} A^{-1}$

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