Question:
If $A$ and $B$ are invertible square matrices of the same order then $(A B)^{-1}=?$
A. $A B^{-1}$
B. $A^{-1} B$
C. $\mathrm{A}^{-1} \mathrm{~B}^{-1}$
D. $B^{-1} A^{-1}$
Solution:
$(A B)^{-1}=B^{-1} A^{-1}$
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