The angles of elevation of the top of a tower from two points

Solution:

Let  be tower of height m and angle of elevation of the top of tower from two points are and 

Let, m and m and 

The corresponding figure is as follows

So we use trigonometric ratios.

In,

$\Rightarrow \tan \theta=\frac{A B}{A C}$

$\Rightarrow \tan \theta=\frac{h}{4}$

Again in $\triangle A B D$,

$\Rightarrow \tan (90-\theta)=\frac{A B}{A D}$

$\Rightarrow \quad \tan \theta=\frac{9}{h}$

$\Rightarrow \quad \frac{h}{4}=\frac{9}{h}$

$\Rightarrow \quad h=6$

Hence the height of tower is $6 \mathrm{~m}$.