The area of ∆AOB having vertices A(0, 6), O(0, 0) and B(6, 0) is
Question:

The area of ∆AOB having vertices A(0, 6), O(0, 0) and B(6, 0) is
(a) 12 sq units
(b) 36 sq units
(c) 18 sq units
(d) 24 sq units

Solution:

The points A(0, 6), O(0, 0) and B(6, 0) can be plotted on the Cartesian plane as follows:

Here, ∆AOB is a right triangle right angled at O.

OA = 6 units and OB = 6 units

$\therefore$ Area of $\Delta \mathrm{AOB}=\frac{1}{2} \times \mathrm{OA} \times \mathrm{OB}=\frac{1}{2} \times 6 \times 6=18$ square units

Hence, the correct answer is option (c).

 

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