The base of a right triangle. is 48 cm and its hypotenuse is 50 cm long.

(c) 336 cm2

Let $\triangle P Q R$ be a right-angled triangle and $\mathrm{PQ} \perp \mathrm{QR}$.

Now,

$P Q=\sqrt{P R^{2}-Q R^{2}}$

$=\sqrt{50^{2}-48^{2}}$

$=\sqrt{2500-2304}$

$=\sqrt{196}$

$=14 \mathrm{~cm}$

$\therefore$ Area of triangle $=\frac{1}{2} \times Q R \times P Q=\frac{1}{2} \times 48 \times 14=336 \mathrm{~cm}^{2}$