Question:
The container shown in the figure has two chambers, separated by a partition, of volumes V1 = 2.0 litre and V2 = 3.0 litre. The chambers contain μ1 = 4.0 and μ2 = 5.0 moles of a gas at pressure p1 = 1.00 atm and p2 = 2.00 atm. Calculate the pressure after the partition is removed and the mixture attains equilibrium.
Solution:
For an ideal gas, PV = μRT
P1V1 = μ1R1T1
P2V2 = μ2R2T2
P1 = 1 atm
P2 = 2 atm
V1 = 2L
V2 = 3L
T1 = T = T2
μ1 = 4
μ2 = 5
Substituting all the values we get, P = 1.6 atm
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