The correct statement about
Question:

The correct statement about $\mathrm{B}_{2} \mathrm{H}_{6}$ is:

  1. Terminal B-H bonds have less p-character when compared to bridging bonds.

  2. The two B-H-B bonds are not of same length

  3. All B-H-B angles are of $120^{\circ}$

  4. Its fragment, $\mathrm{BH}_{3}$, behaves as a Lewis base


Correct Option: 1

Solution:

– $\quad \theta_{2}>\theta_{1}, \therefore \mathrm{B}-\mathrm{H}$ (terminal) having less $\mathrm{p}-$ character as compare to bridge bond.

– Both B-H-B bridge bond having same bond length.

– B-H-B bond angle is $\approx 90^{\circ}$

– $\quad \mathrm{BH}_{3}$ is $\mathrm{e}^{-}$deficient species and therefore act as lewis acid

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