The curved surface area of a cylindrical road is 132

Consider $h$ to be the height of the cylindrical rod.

Given:

Radius, $r=0.35 \mathrm{~cm}$

Curved surface area $=132 \mathrm{~cm}^{2}$

We know :

Curved surface area $=2 \times \pi \times \mathrm{r} \times \mathrm{h}$

$132=2 \times \frac{22}{7} \times 0.35 \times \mathrm{h}$

$h=\frac{132 \times 7}{2 \times 22 \times 0.35}$

$h=60$

Therefore, the length of the cylindrical rod is $60 \mathrm{~cm}$.