The difference between degree

$y^{2}=a\left(x+\frac{\sqrt{a}}{2}\right)=a x+\frac{a^{3 / 2}}{2}$

$\Rightarrow 2 \mathrm{yy}^{\prime}=\mathrm{a}$

put in equation (1)

$y^{2}=\left(2 y y^{\prime}\right) x+\frac{\left(2 y y^{\prime}\right)^{3 / 2}}{2}$

$\left(\mathrm{y}^{2}-2 \mathrm{xy} \mathrm{y}^{\prime}\right)=\frac{\left(2 \mathrm{yy}^{\prime}\right)^{3 / 2}}{2}$

squaring

$\left(y^{2}-2 x y y^{\prime}\right)^{2}=\frac{y^{3}\left(y^{\prime}\right)^{3}}{2}$

$\therefore$ order $=1$

degree $=3$