The first and the last term of an AP are 17 and 350 respectively

Solution:

Given that,

$a=17$

$\ell=350$

d = 9

Let there be n terms in the A.P.

$\ell=a+(n-1) d$

350 = 17 + (n – 1)9

333 = (n – 1)9

(n – 1) = 37

n = 38

$\mathrm{S}_{\mathrm{n}}=\frac{\mathrm{n}}{2}(\mathrm{a}+\ell)$

$\Rightarrow S_{n}=\frac{38}{2}(17+350)=19(367)=6973$

Thus, this A.P. contains 38 terms and the sum of the terms of this A.P. is $6973 .$