Question:
The following system of linear equations
$2 x+3 y+2 z=9$
$3 x+2 y+2 z=9$
$x-y+4 z=8$
Correct Option: , 4
Solution:
$2 x+3 y+2 z=9$......(1)
$3 x+2 y+2 z=9$........(2)
$x-y+4 z=8$........(3)
$(1)-(2) \Rightarrow-x+y=0 \Rightarrow x-y=0$
from (3) $4 \mathrm{z}=8 \Rightarrow \mathrm{z}=2$
from (1) $2 x+3 y=5$
$\Rightarrow x=y=1$
$\therefore$ system has unique solution
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