Question:
The HCF of 95 and 152, is
(a) 57
(b) 1
(c) 19
(d) 38
Solution:
Using the factor tree for 95, we have:
Using the factor tree for 152, we have:
Therefore,
$95=5 \times 19$
$152=2^{3} \times 19$
$\operatorname{HCF}(95,152)=19$
Hence the correct choice is (c).
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