The interaction energy of London

Question:

The interaction energy of London forces between two particles is proportional to $\mathrm{r}^{\mathrm{x}}$, where $\mathrm{r}$ is the distance between the particles. The value of $x$ is :

  1. 3

  2. -3

  3. -6

  4. 6


Correct Option: , 3

Solution:

For london dispersion forces.

$E \propto \frac{1}{r^{6}}$

Hence $x=-6$

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