The lanthanide ion that would show colour is :
Question:

The lanthanide ion that would show colour is :

  1.  $\mathrm{Gd}^{3+}$

  2.  $\mathrm{Sm}^{3+}$

  3.  $\mathrm{La}^{3+}$

  4. $\mathrm{Lu}^{3+}$


Correct Option: , 2

Solution:

$\mathrm{Sm}=4 f^{6} 6 s^{2}$

$\mathrm{Sm}^{3+}=4 f^{5}=$ Partially filled $f$ orbital

$\therefore \mathrm{Sm}^{3+}$ will be coloured

$\mathrm{Lu}^{3+}=4 f^{14}=$ colourless.

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