Question:
The number of different four digit numbers that can be formed with the digits 2, 3, 4, 7 and using each digit only once is
A. 120
B. 96
C. 24
D. 100
Solution:
C. 24
Explanation:
We know that,
nPr=
$\frac{n !}{(n-r) !}$
Four digit numbers that can be formed with the digits 2, 3, 4, 7 and using each digit only once
=4P4 = 4! = 24
Hence, Option (C) 24 is the correct answer.
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