Question:
The number of four-digit numbers strictly greater than 4321 that can be formed using the digits $0,1,2,3,4,5$ (repetition of digits is allowed) is :
Correct Option: , 4
Solution:
(1) The number of four-digit numbers Starting with 5 is equal to $6^{3}=216$
(2) Starting with 44 and 55 is equal to $36 \times 2=72$
(3) Starting with 433,434 and 435 is equal to $6 \times 3=18$
(3) Remaining numbers are $4322,4323,4324,4325$ is equal to 4 so total numbers are
$216+72+18+4=310$
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.