Question:
The output characteristics of a transistor is shown in the figure. When $\mathrm{V}_{\mathrm{CE}}$ is $10 \mathrm{~V}$ and $\mathrm{I}_{\mathrm{C}}=4.0 \mathrm{~mA}$, then value of $\beta_{\mathrm{ac}}$ is_______
Solution:
(150)
At $V_{C E}=10 \mathrm{~V}$ and $I_{C}=4 \mathrm{~mA}$
Change in base current, $\Delta I_{B}=(30-20)=10 \mu \mathrm{A}$
Change in collector current, $\Delta I_{C}=(4.5-3)=1.5 \mathrm{~mA}$
$\beta=\left(\frac{\Delta I_{C}}{\Delta I_{B}}\right)=\frac{1.5 \mathrm{~mA}}{10 \mu \mathrm{A}}=150$
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