The paint in a certain container is sufficient to paint an area equal to 9.375 m2.

Solution:

Total surface area of one brick = 2(lb + bh + lh)

$=[2(22.5 \times 10+10 \times 7.5+22.5 \times 7.5)] \mathrm{cm}^{2}$

$=2(225+75+168.75) \mathrm{cm}^{2}$

$=(2 \times 468.75) \mathrm{cm}^{2}$

$=9375 \mathrm{~cm}^{2}$

Let n bricks can be painted out by the paint of the container.

Area of $n$ bricks $=(n \times 937.5) \mathrm{cm}^{2}=937.5 \mathrm{n} \mathrm{cm}^{2}$

Area of $n$ bricks $=(n \times 937.5) \mathrm{cm}^{2}=937.5 n \mathrm{~cm}^{2}$

Area that can be painted by the paint of the container $=9.375 \mathrm{~m}^{2}=93750 \mathrm{~cm}^{2}$

$\therefore 93750=937.5 n$

$n=100$

Therefore, 100 bricks can be painted out by the paint of the container.