The perimeters of two similar triangles are 25 cm and 15 cm respectively.
Question:

The perimeters of two similar triangles are 25 cm and 15 cm respectively. If one side of first triangle is 9 cm, what is the corresponding side of the other triangle?

Solution:

It is given that perimeter of two similar triangle are $25 \mathrm{~cm}$ and $15 \mathrm{~cm}$ and one side $9 \mathrm{~cm}$.

We have to find the other side.

Let the corresponding side of the other triangle be x cm.

Since ratio of perimeter $=$ ratio of corresponding side

25 cm15 cm=9 cmx

$25 \mathrm{~cm} \times x=9 \mathrm{~cm} \times 15 \mathrm{~cm}$

$x=\frac{135 \mathrm{~cm}}{25 \mathrm{~cm}}$

$x=5.4 \mathrm{~cm}$

Hence $x=5.4 \mathrm{~cm}$