The product of the zeros of x3 + 4x2 + x − 6 is

Question:

The product of the zeros of $x^{3}+4 x^{2}+x-6$ is

(a) $-4$

(b) 4

(c) 6

(d) $-6$

Solution:

Given $\alpha, \beta, \gamma$ be the zeros of the polynomial $f(x)=x^{3}+4 x^{2}+x-6$

Product of the zeros $=\frac{\text { Constant term }}{\text { Coefficient of } x^{3}}=\frac{-(-6)}{1}=6$

The value of Product of the zeros is 6.

Hence, the correct choice is $(\mathrm{c})$

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Comments

Hitj
July 3, 2023, 6:35 a.m.
Nice
Hitj
July 3, 2023, 6:35 a.m.
Nice
Hitj
July 3, 2023, 6:35 a.m.
Nice
Hitj
July 3, 2023, 6:35 a.m.
Nice
CD
June 29, 2023, 6:41 p.m.
Eh Fn
CD
June 29, 2023, 6:35 a.m.
Eh Fn
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