The radii of the ends of a bucket of height 24 cm

Question:

The radii of the ends of a bucket of height 24 cm are 15 cm and 5 cm. Find its capacity. (Take π = 22/7)

Solution:

Height of a bucket $=24 \mathrm{~cm}$

$R=15 \mathrm{~cm}$

$r=5 \mathrm{~cm}$

Therefore,

Capacity of the bucket

$=\frac{\pi h}{3}\left[h^{2}+R r+r^{2}\right]$

$=\frac{22}{7} \times \frac{24}{3} \times\left[(15)^{2}+15 \times 5+(5)^{2}\right]$

$=8171.42 \mathrm{~cm}^{3}$

 

Leave a comment

Close

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now