The rate of a reaction doubles
Question:

The rate of a reaction doubles when its temperature changes from $300 \mathrm{~K}$ to $310 \mathrm{~K}$. Activation energy of such a reaction will be

$\left(\mathrm{R}=8.314 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}\right.$ and $\left.\log 2=0.301\right)$

1. $53.6 \mathrm{~kJ} \mathrm{~mol}^{-1}$

2. $48.6 \mathrm{~kJ} \mathrm{~mol}^{-1}$

3. $58.5 \mathrm{~kJ} \mathrm{~mol}^{-1}$

4. $60.5 \mathrm{~kJ} \mathrm{~mol}^{-1}$

Correct Option: 1

Solution: