Question:
The simplest form of $\frac{1095}{1168}$ is
(a) $\frac{17}{26}$
(b) $\frac{25}{26}$
(c) $\frac{13}{16}$
(d) $\frac{15}{16}$
Solution:
(d) $\frac{15}{16}$
$\frac{1095}{1168}=\frac{1095 \div 73}{1168 \div 73}=\frac{15}{16}$
Hence, HCF of 1095 and 1168 is 73.
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