The simplest form of
Question:

The simplest form of $\frac{1095}{1168}$ is

(a) $\frac{17}{26}$

(b) $\frac{25}{26}$

(c) $\frac{13}{16}$

(d) $\frac{15}{16}$

Solution:

(d) $\frac{15}{16}$

$\frac{1095}{1168}=\frac{1095 \div 73}{1168 \div 73}=\frac{15}{16}$

Hence, HCF of 1095 and 1168 is 73.

 

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