The sum of the roots of the equation
Question:

The sum of the roots of the equation $x^{2}-6 x+2=0$ is

(a) 2
(b) −2
(c) 6
(d) −6

 

Solution:

(c) 6

Sum of the roots of the equation $x^{2}-6 x+2=0$ is

$\alpha+\beta=\frac{-b}{a}=\frac{-(-6)}{1}=6$, where $\alpha$ and $\beta$ are the roots of the equation.

 

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