The symmetric difference of A
Question:

The symmetric difference of A = {1, 2, 3} and B = {3, 4, 5} is

(a) {1, 2}

(b) {1, 2, 4, 5}

(c) {4, 3}

(d) {2, 5, 1, 4, 3}

Solution:

(b) {1, 2, 4, 5}

Here,

A = {1, 2, 3} and B = {3, 4, 5}

The symmetric difference of A  and B is given by :-

$(A-B) \cup(B-A)$

Now, we have:

$(A-B)=\{1,2\}$

 

$(B-A)=\{4,5\}$

$(A-B) \cup(B-A)=\{1,2,4,5\}$

Administrator

Leave a comment

Please enter comment.
Please enter your name.