The value of S in

Question:

The value of $S$ in $\frac{1}{3}+S=\frac{2}{5}$ is

(a) $\frac{4}{5}$

(b) $\frac{1}{15}$

(c) 10

(d) 0

Solution:

(b) Given, $\frac{1}{3}+S=\frac{2}{5}$

$\Rightarrow \quad S=\frac{2}{5}-\frac{1}{3}$ $\left[\right.$ transposing $\frac{1}{3}$ to RHS $]$

$\Rightarrow \quad S=\frac{6-5}{15}$ [taking LCM in RHS]

$\therefore \quad S=\frac{1}{15}$

 

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