The width of each of the five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10.
Question:
The width of each of the five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10. The upper class limit of the highest class is
(a) 45
(b) 25
(c) 35
(d) 40
Solution:
(c) 35
We have:
Class width = 5
Lower class limit of the lowest class = 10
Now,
Upper class limit of the highest class $=10+5 \times 5=35$
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