There are four men and six women on the city council.

Question:

There are four men and six women on the city council. If one council member is selected for a committee at random, how likely is it that it is a woman?

Solution:

There are four men and six women on the city council.

As one council member is to be selected for a committee at random, the sample space contains 10 (4 + 6) elements.

Let A be the event in which the selected council member is a woman.

Accordingly, $n(\mathrm{~A})=6$

$\therefore \mathrm{P}(\mathrm{A})=\frac{\text { Number of outcomes favourable to } \mathrm{A}}{\text { Total number of possible outcomes }}=\frac{n(\mathrm{~A})}{n(\mathrm{~S})}=\frac{6}{10}=\frac{3}{5}$

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