Total number of 6-digit numbers in

Question:

Total number of 6-digit numbers in which only and all the five digits $1,3,5,7$ and 9 appear, is :

  1. $\frac{5}{2}(6 !)$

  2. $5^{6}$

  3. $\frac{1}{2}(6 !)$

  4. 6 !


Correct Option: 1

Solution:

Total number of 6-digit numbers in which only and all the five digits $1,3,5,7$ and 9 is

${ }^{5} \mathrm{C}_{1} \times \frac{6 !}{2 !}$

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